NEET Solved Paper 2019 Question 53
Question: A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population? [NEET 5-5-2019]
Options:
A) 0.16(AA); 0.48 (Aa); 0.36 (aa)
B) 0.16 (AA); 0.36(Aa); 0.48 (aa)
C) 0.36 (AA); 0.48 (Aa); 0.16 (aa)
D) 0.16 (AA); 0.24 (Aa); 0.36 (aa)
Show Answer
Answer:
Correct Answer: A
Solution:
- Now, let’s calculate these frequencies:
-
Frequency of homozygous dominant (AA): [ p^2 = (0.4)^2 = 0.16 ]
-
Frequency of heterozygous (Aa): [ 2pq = 2 \times 0.4 \times 0.6 = 0.48 ]
-
Frequency of homozygous recessive (aa): [ q^2 = (0.6)^2 = 0.36 ]
So, the frequencies are:
- Homozygous dominant (AA): 0.16
- Heterozygous (Aa): 0.48
- Homozygous recessive (aa): 0.36
BETA
